Question

integration of x(tan-1x)2

Answer 1

we know that,
integration xtan inverse x= integration (tan inverse x)(x)

=(tan inverse x) integration (x)dx - [integration {d/dx (tan inverse x)} { integration (x)dx} dx]

= [(tan inverse x)x square /2] - [integration (1/1+x square).(x square/2)]

= (x square/2) (tan inverse x) - 1/2 integration ( x square/ 1 + x square)dx

= ?








you help this formulla


integration (dx/a square+ x square) = 1/a tan inverse x/a + c