Question

integration of x.tanx​

Answer 1

sxtanndx I think this is the best

Answer 2

Step-by-step explanation:

$= > \int \: x.tanx \: dx$

Apply this formula

$\int u.vdx = u \int \: v.dx - \int \frac{du}{dx} ( \int \: v.dx)dx$

$\int \: x.tanx = x \int \: tanx.dx - \int \: \frac{dx}{dx} ( \int \: tanx.dx)dx \\ \\ \therefore \int x.tan x = - x ln(cosx ) - \int - (1) ln(cosx) dx \\ \\ \therefore \int \: x.tanx = - x ln(cosx) + \int \: ln(cosx) dx \\ \\ \therefore \int \: x.tanx = - x ln(cosx) + cosx ln(cosx) - cosx + c$