integration of x/(x +1)^2
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Answered by
1
Answer:
x/(x+1)^2
Step-by-step explanation:
/x by (x-1)^2 dx
u=x-1 ==>x=u+1
du = dx
==>/x by (x-1)^2 dx= / u+1 by u^2 du
=/ u by u^2 du+/1 by u^2 du
In u-1 by u + c =In (x-1) - 1 by x-1 +C
==>/x by (x-1)^2 dx =1n (x-1)-1 by x-1 +C
MARK AS BRANILYLIST
Answered by
0
Answer:
I don't know the answer bro
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