Math, asked by ns2132500, 5 months ago

integration of x/(x +1)^2​

Answers

Answered by pushpach9640
1

Answer:

x/(x+1)^2

Step-by-step explanation:

/x by (x-1)^2 dx

u=x-1 ==>x=u+1

du = dx

==>/x by (x-1)^2 dx= / u+1 by u^2 du

=/ u by u^2 du+/1 by u^2 du

In u-1 by u + c =In (x-1) - 1 by x-1 +C

==>/x by (x-1)^2 dx =1n (x-1)-1 by x-1 +C

MARK AS BRANILYLIST

Answered by sushilyadav1929
0

Answer:

I don't know the answer bro

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