Question

Integration of (x²+3x+4)⁴ dx​

Answer 1

$\int(x ² + 3x + 4)⁴dx$

= $\frac{ \frac{ {x}^{3} }{3} + 3 \times( \frac{x {}^{2} }{2}) + 4x }{5}$

$= \frac{1}{5} ( \frac{ {x}^{3} }{3} + \frac{3x {}^{2} }{2} + 4x) + c$

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Note :

$\int x {}^{n}dx = \frac{x {}^{n + 1} }{n + 1} (n ≠ - 1)$

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