Question

Integration of x²×sec²(x³) dx

Answer 1

∫ x² Sec²(x³)dx = (1/3) Tan(x³)  + c  

Step-by-step explanation:

∫ x² Sec²(x³)dx

Let say  x³  = y

=> 3x²dx = dy

=> x²dx =dy/3

= ∫ (1/3) Sec²(y)dy

= (1/3) ∫  Sec²(y)dy

= (1/3) Tany  + c

= (1/3) Tan(x³)  + c

∫ x² Sec²(x³)dx = (1/3) Tan(x³)  + c  

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