Question

Integration of x²(x-1)².dx​

Answer 1

Answer:

=integ.of (x^2+1)/(x+1)^2.dx

I=integ. of [(x+1)^2–2x]/(x+1)^2.dx

I=integ. of [ 1 - (2x+2–2)/(x+1)^2].dx

I=. of [1–2(x+1)/(x+1)^2 +2/(x+1)^2].dx

I= integ.of,[1–2/(x+1)+2.1/(x+1)^2].dx

I=x-2 log (x+1)-2/(x+1)+C