Question

integration of x²/x⁴+x²+1 dx​

Answer 1

Answer:

integral(x^2/x^4 + x^2 + 1) dx = x^3/3 + x - 1/x + constant

Step-by-step explanation:

integral( 1/x^2+x^2+1) dx

= integral (x^-2+x^2+1)dx

=( x^-2+1)/(-2+1)+x^3/3+x +constant

=x^-1/-1+x^3/3+x+constant

=-(1/x)+x^3/3+x+constant

=x^3/3 +x-1/x+constant

integral(x^2/x^4 + x^2 + 1) dx = x^3/3 + x - 1/x + constant