integration of x³/√1-x^4
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∫x³÷(1-x⁴).dx
⇒-1/4∫(-4x³)÷(1 - x⁴).dx
we know,
∫f'(x)÷√f(x).dx = 2√f(x) + C
⇒-1/4 × 2√(1 - x⁴) + C
⇒ -1/2 √(1 - x⁴) + C
⇒-1/4∫(-4x³)÷(1 - x⁴).dx
we know,
∫f'(x)÷√f(x).dx = 2√f(x) + C
⇒-1/4 × 2√(1 - x⁴) + C
⇒ -1/2 √(1 - x⁴) + C
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