integration of xsinsquarex
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Therefore the integral equals the integral of (1/2)(1-cos(2x)). We know the integral of cos(2x) dx is (1/2)*(sin(2x)). Thus the integral of sin^2(x)dx equals (x-(1/2)*sin(2x))/2.
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Using integration by substitution together with the know intergal √sin(x)dx=-cos(x) +c we first let you 2x=du=2dx
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