Math, asked by Anonymous, 1 year ago

integration please..........

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Answers

Answered by Anonymous
3
sunbath luck Katy ms
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Answered by nagathegenius
0

Answer:

Step-by-step explanation:

=∫x^2 +x+1  dx /x^2(x+2)

=∫x^2 dx / x^2(x+2) + ∫x+2 dx / x^2(x+2) -∫dx / x^2(x+2)

=∫ dx / x+2 + ∫dx/x^2 -∫dx/x^2(x+2)

=ln (x+2) -1/x -∫dx/x^2(x+2)

∫dx / x^2(x+2)

∫x^-2(x+2)^-1 dx

let x+2=t

dx=dt

∫(t-2)^-2*(t) dt

∫dt / t(t-2)^2

apply integration by partial fractions

you will get definately get answer

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