Question

➡INTEGRATION⬅

Q. Integrate Cos X dX applying limits as -π/2 and π/2 .

Answer 1

sorry for the image ...I hope it helps

Answer 2

we know the integration of cos dx = sinx + constant.
now here we have to take limit also.
so,
$\int\limits^\frac{\pi}{2}_\frac{-\pi}{2} {cosx} \, dx$

$[sinx]\limits^\frac{\pi}{2}_\frac{-\pi}{2}$

$[sin\frac{\pi}{2} - sin(-\frac{\pi}{2})]$

$[1 - (-sin\frac{\pi}{2})]$

$1 + 1$

2