integration sin^-1 (cos 5x) dx ?Answer
Answers
Answered by
1
Answer:
the ansnwer is
4
sin
4
x
−
3
2sin
3
x
+
2
sin
2
x
+c.
Step-by-step explanation:
∫sinxcos
5
xdx
∫sinxcos
4
xcosxdx
Let sinx=u
⇒cosxdx=du
⇒∫sinxcos
5
xdx=∫u(1−u
2
)
2
du
=∫u(u
2
−2u+1)du
=∫(u
3
−2u
2
+u)du
=
4
u
4
−
3
2u
3
+
2
u
2
+c
=
4
sin
4
x
−
3
2sin
3
x
+
2
sin
2
x
+c
Answered by
1
Answer:
hope this helps
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