integration sin³(2x+3)
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★ GOOD NIGHT ★
Sin³ ( 2x + 3 ) =
{1 - Cos² ( 2x + 3 )} × ( Sin ( 2x + 3 )
put Cos ( 2x + 3 ) = z
DIFFERENTIATE both sides w.r.t x we have
- 2Sin ( 2x + 3 ) dx = dz
=>
integration of -(1/2)×( 1 - z² ) dz
=>
(-1/2) × ( z - z³/3 )
=>
(-1/2) × ( Cos ( 2x + 3 ) - Cos³ ( 2x + 3 )/3 )
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