Question

integration (sinx)^-1/2 coax.dx​

Answer 1

Answer:

2 $sin^{1/2} x$ + c

Step-by-step explanation:

   $sin^{-1/2} x$ * cos x dx

= $z^{-1/2} dz$     [Let, $sinx$ = z    =>$cosx dx$ = $dz$ ]

= 2$z^{1/2}$ + c       [ c is a constant]

= 2 $sin^{1/2} x$ + c