Question

Integration with limit 1 to -1 of x³ ​

Answer 1

Step-by-step explanation:

Because the equation is true for any real number, it is true for x=c.

Then 3c5+96=∫ccg(t)dt=0.

Thus, 3c5=−96, so c5=−32, so c=(−32)1/5=−2.