Math, asked by nitukumarihjp1, 19 days ago

integrators are placed in such a way that their sum is 1 and product is 36 what is the sum of their cube value.​

Answers

Answered by IPavanI
0

Answer:-

integers will be (6,-2,-3)

the sum of their product is 181

Step-by-step explanation:

6+(-2)+(-3)= 1

6*(-2)*(-3)=36

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