Question

integreation of cotx tanx divided by secant squarex minus 1​

Answer 1

Answer:   $-cotx-x+c$

Step-by-step explanation:

$\int {\frac{(cotx)(tanx)}{sec^{2}x -1 } \, dx$

$\int {\frac{(\frac{1}{tanx} )(tanx)}{sec^{2}x -1 } \, dx$

$\int {\frac{1}{sec^{2}x -1 } \, dx$

$\int {\frac{1}{tan^{2}x } \, dx$

$\int cot^{2}x \, dx$

$\int {cosec^{2}x -1} \, dx$

$-cotx-x+c$