integrity (x-3) /(x-1) ³ ex dx
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Step-by-step explanation:
Let I=∫e
x
{
(x−1)
3
x−3
}dx=∫e
x
{
(x−1)
2
x−1−2
}dx
=∫e
x
{
(x−1)
2
1
−
(x−1)
3
2
}dx
Let f(x)=
(x−1)
2
1
⇒f
′
(x)=
(x−1)
3
−2
Now know that, ∫e
x
{f(x)+f
′
(x)}dx=e
x
f(x)+C
∴I=
(x−1)
2
e
x
+C
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