integrte sincube x in upperlimit pi by 2 and lower limit 0
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I hope this helps
∫
π
2
0
sin
3
x
d
x
=
∫
π
2
0
(
1
−
cos
2
x
)
sin
x
d
x
=
∫
π
2
0
(
sin
x
−
cos
2
x
sin
x
)
d
x
=
(
−
cos
x
+
1
3
cos
3
x
)
∣
∣
∣
π
2
0
=
(
−
0
+
1
3
⋅
0
)
−
(
−
1
+
1
3
)
=
2
3
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