Question

Intelligent people solve it please
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Answer 1

Answer:

=> (x³+12x+6x^2+8)/(x³+12x-6x^2-8) = (y³+27y+9y²+27)/ (y³+27y-9y²-27)

The numerators are in the form

(a³+b³+3a²b+3ab²) and denominators are in the form (a³- b^3 -3a²b+3ab²).

=> [a³+b³+3a²b+3ab² = (a+b)³] and

[a³-b³-3a²b +3ab² = (ab)³]

=> (x+2) ³/(x-2)³ = (y+3)³/(y-3)³

→ take cube root on both sides we get,

=> (x+2)/(x-2) = (y+3)/(y-3)

Again apply componendo and dividendo rule!

=>(x+2+x-2)/(x+2-x+2)=(y+3+y-3)/(y+3-y +3)

=> 2x/4 = 2y/6

=> x/2= y/3

=> x/y = 2/3

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Answer 2

Answer:

Option A 2:3

I hope you have understood the ans