Question

intelligent person can answer : prove that (cos thita I - sin thita + 1) /(cos thita + sin thita - 1) = cosrc thita + cot thita

Answer 1

Answer:

LHS = (cos∅ - sin∅ + 1)/(cos∅ + sin∅-1)

dividing sin∅ both Numerator and denominator.

= (cos∅/sin∅ - sin∅/sin∅ + 1/sin∅)/(cos∅/sin∅ + sin∅/sin∅ - 1/sin∅)

= (cot∅ - 1 + cosec∅)/(cot∅ + 1 - cosec∅)

now, put 1 = cosec²∅ - cot²∅ in numerator

= {cot∅ + cosec∅ - (cosec²∅-cot²∅)}/(cot∅-cosec∅ +1)

= (cosec∅+cot∅)(1 - cosec∅ + cot∅)/(cot∅-cosec∅+1)

= cosec∅ + cot∅ = RHS

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