Math, asked by sharathshetty26, 11 months ago

intelligents please send me the answer

Attachments:

Strikingsagar: A-d, a, a+d are in ap
sum=27
a-d+a+a+d=27
3a=27
a=27/3
a=9
product =648
(a-d) (a+d)a=648
(a^2 - d^2)(a) =648
(81-d^2)(9)=648
81-d^2=648/9
81-d^2=72
d^2=81-72
d^2=9
d=3
a=9,d=3
a-d= 9-3=6
a=9
a+d=9+3=12
numbers are 6,9,12

Answers

Answered by charan13249

here mate the answer in attachment

Attachments:

amit1398: yes

amit1398: Rajasthan

sharathshetty26: įam ask another question you see & ans

sharathshetty26: 3x +3a = 27. but how X+ A = 9

sharathshetty26: please explain

Answered by Steph0303

Answer:

Step-by-step explanation:

Let the terms of AP be ( a - d ) ( a ) and ( a + d )

Sum = 27

⇒ a - d + a + a + d = 27

⇒ 3a + 0d = 27

⇒ a = 27 / 3 = 9

Also Product of the terms is 648.

⇒ ( a + d ) ( a - d ) ( a ) = 648

⇒ ( 9 + d ) ( 9 - d ) ( 9 ) = 648

⇒ ( 81 - d² ) 9 = 648

⇒ 81 - d² = 648 / 9

⇒ 81 - d² = 72

⇒ 81 - 72 = d²

⇒ 9 = d²

⇒ d = √9 = ± 3

Therefore the AP can be ( 9 - 3 ) , ( 9 ), ( 9 + 3 ) which is 6, 9, 12

Or else, it can be ( 9 - ( -3 ) ), ( 9 ), ( 9 - 3 ) which is 12, 9, 6.

Hope it helped !!

Cheers !!

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