intelligents please send me the answer
Attachments:
Answers
Answered by
2
here mate the answer in attachment
Attachments:
Answered by
1
Answer:
Step-by-step explanation:
Let the terms of AP be ( a - d ) ( a ) and ( a + d )
Sum = 27
⇒ a - d + a + a + d = 27
⇒ 3a + 0d = 27
⇒ a = 27 / 3 = 9
Also Product of the terms is 648.
⇒ ( a + d ) ( a - d ) ( a ) = 648
⇒ ( 9 + d ) ( 9 - d ) ( 9 ) = 648
⇒ ( 81 - d² ) 9 = 648
⇒ 81 - d² = 648 / 9
⇒ 81 - d² = 72
⇒ 81 - 72 = d²
⇒ 9 = d²
⇒ d = √9 = ± 3
Therefore the AP can be ( 9 - 3 ) , ( 9 ), ( 9 + 3 ) which is 6, 9, 12
Or else, it can be ( 9 - ( -3 ) ), ( 9 ), ( 9 - 3 ) which is 12, 9, 6.
Hope it helped !!
Cheers !!
Similar questions
sum=27
a-d+a+a+d=27
3a=27
a=27/3
a=9
product =648
(a-d) (a+d)a=648
(a^2 - d^2)(a) =648
(81-d^2)(9)=648
81-d^2=648/9
81-d^2=72
d^2=81-72
d^2=9
d=3
a=9,d=3
a-d= 9-3=6
a=9
a+d=9+3=12
numbers are 6,9,12