Question

Intensity of central fringe in interference pattern is
0.01 W/m then find intensity at a point having path
difference 1/3 on screen from centre (in mW/m?)

Answer 1

The intensity at a point having path  difference 1/3 on screen from center is 2.5 mW/m^2

Explanation:

As we know that intensity relation on the screen is given as

$I = 4I_o cos^2(\frac{\phi}{2})$

here we know that

$\phi = \frac{2\pi}{\lambda}(path\: difference)$

here we know that

$\delta x = \frac{1}{3}\lambda$

so we have

$\phi = \frac{2\pi}{\lambda}(\frac{\lambda}{3})$

$\phi = \frac{2\pi}{3}$

now we have

$4I_o = 0.01 W/m$

again we have

$I = 4I_o cos^2(\pi/3)$

$I = I_o$

$I = 2.5 mW/m^2$

#Learn

Topic : Interference of light

https://brainly.in/question/2741777

Answer 2

Answer:

Check the pic for answer