Question

intensity of electric field at a distance of 1 metre from a point charge is 450 volt per metre find the magnitude of the charge​

Answer 1

Answer:

$E = \frac{kq}{ {r}^{2} }$

$450 = \frac{9 \times {10}^{9} \times q}{1} \\ \\ q = \frac{450}{9 \times {10}^{9} } \\ \\ q = 50 \times {10}^{ - 9} \\ q = 5 \times {10}^{ - 8} \: c$

Answer 2

Answer:

Due to rude words I cannot post directly..

so here's the ss of my answer..