Physics, asked by navneettiwari844446, 7 months ago

intensity of electric field at point c in the given figure​

Answers

Answered by sparsh7637
0

Answer:

there is no figure

Explanation:

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Answered by YuvrajBoora
0

Answer:

Consider an infinitesimal element as shown in figure (black) of length dx.

The amount of charge in the infinitesimal element is dq=λdx=αx dx

The distance between the charge element and the point is d+x.

Thus, the electric field due to the infinitesimal charge element is dE=

4πϵ

0

(d+x)

2

dq

=

4πϵ

0

(d+x)

2

αx

dx

Thus, the net electric field due to the rod is given by

E=∫dE=

0

L

4πϵ

0

(d+x)

2

αx

dx=

4πϵ

0

α

0

L

(d+x)

2

(d+x)−d

dx=

4πϵ

0

α

[

0

L

d+x

1

dx+d

0

L

(d+x)

2

1

dx]

0

L

d+x

1

dx=[ln(d+x)]

0

L

=ln(d+L)−ln(d)=ln(1+

d

L

)

0

L

(d+x)

2

1

dx=[

d+x

1

]

0

L

=

d+L

1

d

1

=−

d(d+L)

L

Thus, E=

4πϵ

0

α

[ln(1+

d

L

)−d(

d(d+L)

L

)]=

4πϵ

0

α

[ln(1+

d

L

)−

L+d

L

]

solution

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