Interest earned on an amount at 11% rate in S.I for 4 years equal to the interest earned when same amount is invested at some interest in a scheme with C.I for 2 years.If Interest earned in C.I for 3 years is 10920 then find out the initial amount invested.
Answers
Step-by-step explanation:
Solution :-
Let the invested amount be Rs. X
Rate of interest (R) = 11%
Time (T) = 4 years
We know that
Simple Interest = PTR/100
=> S.I = (X×4×11)/100
=> S.I = Rs. 44X/100 ----------(1)
Given that
Time (T) = 2 years
n = 2
We know that
Amount (A) = P[1+(R/100)]^n
=> A = X[1+(R/100)]²
=> A = X[(100+R)/100]²
We know that
Compound Interest = Amount - Principle
=> C.I. = X[(100+R)/100]² - X
=> C.I. = X[{(100+R)/100}²-1]
=> C.I. = X[(100+R)²-100²]/100²
=> C.I. = X[100²+200R+R²-100²]/100²
=> C.I. = X(200R+R²)/100² --------(2)
According to the given problem
S.I. for 4 years = C.I. for 2 years
From (1) & (2)
=> (1) = (2)
=> 44X/100 = X(200R+R²)/100²
On applying cross multiplication then
=> 44X×100² = 100X(200R+R²)
=> 440000X = 100X(200R+R²)
On cancelling 100X both sides then
=> 4400 = 200R+R²
=> R²+200R-4400 = 0
=> R²+220R-20R-4400 = 0
=> R(R+220)-20(R+220) = 0
=> (R+220)(R-20) = 0
=> R+220 = 0 (or) R-20 = 0
=> R = -220 (or) R = 20
Rate of interest can't be negative.
So, R = 20%
Now,
Given Interest earned for 3 years
= Rs. 10920
Time period = 3 years
n = 3
Now.
We know that
Amount (A) = P[1+(R/100)]^n
=> A = X[1+(20/100)]³
=> A = X[(100+20)/100]³
=> A = X(120/100)³
=> A = X(6/5)³
=> A = X(6/5)×(6/5)×(6/5)
=> A = X(6×6×6)/(5×5×5)
=> A = X(216/125
=> A = Rs. 216X/125
Now
Compound Interest = Amount - Principle
=> 10920 = (216X/125)-X
=> 10920 = (216X-125X)/125
=> 10920 = 91X/125
=> 91X/125 = 10920
=> 91X = 10920×125
=> 91X = 1365000
=> X = 1365000/91
=> X = Rs. 15000
The initial amount invested = Rs. 15000
Answer:-
The amount invested initially is Rs. 15000
Used formulae:-
→ Simple Interest = PTR/100
→ Amount (A) = P[1+(R/100)]^n
→Interest = Amount - Principle
- P = Principle
- T = Time
- R = Rate of Interest
- n = number of times the interest calculated compoundly
- S.I. = Simple Interest
- C.I. = Compound Interest
→ (a+b)² = a²+2ab+b²
Used Method:-
- Prime factorization method