Math, asked by rohitsharma2239, 6 months ago

Interest on Rs 24000 for 1 month at the rate of 10 % per annum is:

Hey mate help me Plz....​

Answers

Answered by Subham200813
6

Step-by-step explanation:

Principal = ₹24,000

Time = 1 month

 =  \frac{1}{12}  \:  \: years

Rate = 10%

Hence,

si \:  =  \:  \frac{p \:  \times  \: r \:  \times  \: t}{100 }

 =  \frac{24000 \times  \frac{1}{12} \times 10 }{100}

 = 200

Answered by pulakmath007
5

Interest on Rs. 24000 for 1 month at the rate of 10 % per annum is Rs. 200

Given :

Rs. 24000 for 1 month at the rate of 10 % per annum

To find :

The interest

Solution :

Step 1 of 2 :

Find principal , time and rate of interest

Principal = P = Rs. 24000

Time = t = 1 month = 1/12 year

Rate of interest = r% = 10%

Step 2 of 2 :

Find the interest

Hence the required interest

\displaystyle \sf{ =  \frac{Prt}{100}   }

\displaystyle \sf{ =Rs. \:  \:   \frac{24000 \times 1 \times 10}{12 \times 100}   }

\displaystyle \sf{ =Rs. \:  \:   200   }

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