Question

Interest P=8000,R=9%,. T=6months (Use 1year=366days)​

Answer 1

Given:-

• Principal (P) = ₹8000.
• Rate of interest (R) = 9%
• Time period (T) = 6 months.

To find:-

• Interest

SolutioN:-

We know that,

Simple interest = $\sf \frac{P \times R \times T}{100}$

In which,

• P is principal.
• R is rate of interest.
• T is time period.

So,

➢Principal (P) = ₹8000.

➢Rate of interest (R) = 9%

➢Time period (T) = 6 months = $\sf \frac{1}{2} years$ (beacuse 1 year consist of 12 months if we talk about half year it consists of 6 months)

Put the value of P , R and T in formula

$\implies \sf \frac{8000 \times 9\times 1 }{100\times 2}$

$\implies \sf \frac{80 \times 9\times 1 }{1 \times 2}$

$\implies \sf 40 \times 9$

$\implies \sf 360$

Therefore,

Interest is Rs 360.