Question

interest sum of three number is 10 and the sum of their square is 38 find the sum of the product of the three numbers taking two at a time​

Answer 1

Answer:

Step-by-step explanation:

given

a+b+c=10

a^2+b^2+c^2=38

ab+bc+ac=?

consider (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ac)

100=38+2(ab+bc+ac)

100-38=2(ab+bc+ac)

62/2=ab+bc+ac

31=ab+bc+ac