Question

interested people can help me for this question it is based on physics yours affectionately ADVAITH................................​

Answer 1

position of image is:

• Image is real
• Imagec is inverted
• Image is fomed at 2F
• Image is same size as of an object

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Answer 2

$we \: have \: f = - 20cm \: (it \: is \: a \: concave \: mirror) \\ object \: distance = u = - 20cm \\ \\ then \: using \: mirror \: formula \\ \\ \frac{1}{f} = - \frac{1}{v} - \frac{1}{u} \\ = > - \frac{1}{20} = \frac{1}{v} - ( - \frac{1}{20} ) \\ = > - \frac{1}{20} = \frac{1}{v} + \frac{1}{20} \\ = > \frac{1}{v} = - \frac{1}{20} - \frac{1}{20} \\ = > \frac{1}{v} = \frac{ - 1 - 1}{20} \\ = > \frac{1}{v} = - \frac{ 2}{20} \\ = > \frac{1}{v} = - \frac{1}{10} \\ = > v = - 10$

hence the position of image is at a distance of 10 cm in front of the mirror. the image is real and inverted.

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