Question

intergal (x÷1+x^2dx)​

Answer 1

Answer:

so the answer of the question is 1/2 log(1+x^2)+c

Step-by-step explanation:

here given function = x/(1+x^2)

Now let 1+x^2 =t

now we will differntiate it independently

so 0+2xdx = dt

= xdx = dt/2

now put values in above given equation

1/2 1/t dt

so it will be 1/2 logt +c

we will again replace t with 1+x^2

so the final answer will be log(1+x^2)/2

HOPE IT HELPS