intergral sin^2x/1+cosx
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Answer:
Step-by-step explanation:
WE have : sin ^2x +cos^2x =1
=sin^2x =1-cos^2x
=sin^2x =(1-cosx)(1+cosx)
Now sin^2x÷1+cosx=(1+cosx)(1-cos)÷(1+cosx)=
=(1-cosx)
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please mark it as brain list answer
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