intergrate (x^2-cosx +1/x) dx
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x^3/3 - sin x + loge x + c
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aashish001:
sorry
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HI MATE......
HERE IS YOUR ANSWER
Given [x^2 - cos x +1/x ] dx,
Then,
= [ x^2 -cos x + 1/x] dx
= x^3 /3 - sin x+ log = x+ c......
Hope it works to you
if work then plz mark as brainleast plz it's an urgent plz
HERE IS YOUR ANSWER
Given [x^2 - cos x +1/x ] dx,
Then,
= [ x^2 -cos x + 1/x] dx
= x^3 /3 - sin x+ log = x+ c......
Hope it works to you
if work then plz mark as brainleast plz it's an urgent plz
:)
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