Question

intergration of 1/x^9​

Answer 1

Answer:

$\int \frac{1}{ {x}^{9} } \: dx\\ \\ = \int {x}^{ - 9} \: dx \\ \\= \frac{{x}^{ - 9 + 1 }}{{ - 9 + 1}} + c\\ \\ = \frac{ {x }^{ - 8} }{ - 8} + c \\\\ = - \frac{1}{ 8 {x}^{8} } + c \\\\ thus \\ \\ \purple{\boxed{ \int \frac{1}{ {x}^{9} } \: dx = - \frac{1}{ 8 {x}^{8} } + c}}$

Answer 2

Step-by-step explanation:

integration of 1/x^9

=integration of x^-9

=x^-9+1/-9+1 +C

=x^-8/-8+C

= -1/8x^8+C

hope so this is correct...