Question

interigation of 3x^3+2 dx​

Answer 1

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Answer 2

Step-by-step explanation:

• We know that d/dx (a^x)= a^x. Log a
• We know that d/dx (a^x)= a^x. Log aLet y = 3^(2–3x) and 2–3x =t. => dt/dx = -3
• We know that d/dx (a^x)= a^x. Log aLet y = 3^(2–3x) and 2–3x =t. => dt/dx = -3y = 3(2–3x)=> y = 3^t. Differentiate with respect to x we get
• We know that d/dx (a^x)= a^x. Log aLet y = 3^(2–3x) and 2–3x =t. => dt/dx = -3y = 3(2–3x)=> y = 3^t. Differentiate with respect to x we getdy/dx = 3^t. Log t.(-3) = -3.3^(2–3x).log 3