interior angle of a a triangle is 40°, exterior angle is 100° find interior opposite angle?
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Step-by-step explanation:
Using the theorem that if the side of a triangle is produced then the interior angle is equal to the sum of two interior opposite angles of the triangle.
Let ΔABC be a triangle where the side BC is produced.
By the theorem we have
∠A+∠B=100
o
…………..(1)
It is given that the interior opposite angles are equal i.e., ∠A=∠B.
∴ Equation (1) becomes
2∠A=100
o
⇒∠A=50
o
⇒∠B=50
o
Using angle sum property of a triangle,
Sum of all angles of a triangle =180
o
⇒∠A+∠B+∠C=180
o
⇒100+∠C=180
o
[from (1)]
⇒∠C=180
o
−100
o
⇒∠C=80
o
.
Hence ∠A=50
o
∠B=50
o
∠C=80
o
.
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