Question

Interior angles of a pentagon are five consecutive multiples
of 3. Find all the angles of the pentagon.
​

Answer 1

Answer:

let the angles be 3x,3x+1,3x+2,3x+3,3x+4

3x+3x+1+3x+2+3x+3x+4=540

15x+10=540

15x=540-10

15x=530

x=530

15

x=36

SO:

3x=3×36

=108

3(x+1)=3×(36+1)

=111

3(x+2)=3×(36+2)

=114

3(x+3)=3×(36+3)

=117

3(x+3)=3×(36+4)

120

The consecutive multiples and angles are 108, 111, 114, 117, 120.

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