Question

Intermolecular forces of attraction are more in

(1) Fluorine (2) Iodine (3) Bromine (4) Chlorine​

Answer 1

Answer:

Explanation:

Since all three of your choices are homo nuclear diatomic (two atoms the same in a molecule), there is no polarity in the molecule so no dipole-dipole forces and no hydro gens so no H-bonding. The only type of inter molecular force possible is London Dispersion forces. These forces depend on the polarizability of the species. By that, I mean the ease with which the electrons can move around and create temporary dipoles in the other-wise non-polar molecule. The larger the species, the further away from the nucleus the outer electrons are and hence the less strongly they are held. This means the bigger atoms will be more polarizable. So, the order from biggest-smallest molecules (strongest to weakest IMF) is iodine, bromine and finally chlorine.

      Fluorine< chlorine < bromine < iodine

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