Question

Internal bisector of angle a of triangle abc meets bc at d and the external bisector of angle a meets bc produced at


e.prove that bd/be is equal to cd/ce

Answer 1

result used: the ratio in which angle bisector of a triangle divides opp side is same as ratio of sides containing the angle
for Internal bisector of angle a of triangle abc meets bc at d
AB/AC=BD/DC
external bisector of angle a meets bc produced at e
AB/AC=BE/EC
from above
BD/DC=BE/EC
rearranging
BD/BE=CD/EC