Question

Internal radius of a capillary tube is 1/28 cm and surface tension of water is 70 dyne/cm,if angle of contact is zero,then water will rise up in the tube up to height

Answer 1

Answer:

Water will rise in the tube upto height 4 cm

Explanation:

As we know that Height raised by liquid in capillary is given as

$H =\frac{2Scos\theta}{\rho g r}$

here we know that

$S = 70 dyne/cm = 70 \times 10^{-3} N/m$

$r = 1/28 cm$

$\theta = 0^o$

$\rho = 1000 kg/m^3$

now we have

$H = \frac{2(70 \times 10^{-3})cos 0}{1000(9.81)(1/28 \times 10^{-2})}$

$H = 4 cm$

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Topic : Capillary Rise in tube

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Answer 2

The height of the water is 4 cm.

Explanation:

Given that,

Radius of capillary tube $r=\dfrac{1}{28}\ cm$

Surface tension = 70 dyne/cm

Angle = 0

We need to calculate the height of the water

Using formula of height

$h=\dfrac{2T\cos\theta}{r\rho g}$

Where, r = radius of the capillary

T = surface tension

g = acceleration due to gravity

Put the value into the formula

$h=\dfrac{2\times70\times10^{-3}\times\cos0}{\dfrac{1}{28}\times10^{-2}\times1000\times9.8}$

$h=4\ cm$

Hence, The height of the water is 4 cm.

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Topic : height of capillary tube

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