Question

internal radius of hemisphere bowl is 21cm ,find the volume of the bowl?

Answer 1

GIVEN:-

• $\rm{Radius\:of\:hemisphere\:bowl= 21cm}$

TO FIND:-

• The Volume of the bowl.

FORMULAE USED:-

• ${\dag{\boxed{\rm{Area\:of\:hemisphere= \dfrac{2}{3}\pi r^3}}}}$

Now,

$\implies\rm{Area\:of\:hemisphere=\dfrac{2}{3}\pi r^3}$

$\implies\rm{Area\:of\:hemisphere=\dfrac{2}{3}\times{\dfrac{22}{7}\times{(21)^3}}}$

$\implies\rm{Area\:of\:hemisphere=\dfrac{2}{\cancel{3}}\times{\dfrac{22}{\cancel{7}}\times{\cancel{21}}\times{\cancel{21}}\times{21}}}$

$\implies\rm{Area\:of\:hemisphere=2\times{22}\times{7}\times{3}\times{21}=19404cm^3}$

Hence, The Volume of the ball is 19404cm³

MORE FORMULAES

$\boxed{\begin{minipage}{5cm}\\ \\ \sf\bf{Volume\:of\:cylinder= \tt \pi r^2h }\\ \\ \tt\bf{T.S.A\:of\:Cylinder= \tt 2\pi r(r+h) }\\ \\ \rm\bf{LSA of Cylinder= \tt 2\pi rh }\end{minipage}}$

Answer 2

Given ,

The radius of sphere = 21 cm

We know that ,

The volume of sphere is given by

Volume = 2/3 × π(r)³

Thus ,

$\sf \mapsto Volume = \frac{2}{3} \times \frac{22}{7} \times {(21)}^{3} \\ \\\sf \mapsto Volume = 44 \times7 \times 3 \times 21 \\ \\ \sf \mapsto Volume = 924 \times 21 \\ \\ \sf \mapsto Volume =19404 \: \: {cm}^{3}$

$\sf \therefore \underline{ {The \: volume \: of \: bowl \: is \: 19404 \: {cm}^{3} }}$