Question

Interpret the following graphs:

Answer 1

1. Distance increases when time increases like a parabola, so m = as²

v = dm/ds = 2as

dv/ds = 2a

so, distance increasing with a constant acceleration.

2. Distance increases then decreases like a downward parabola, so m = -as²

v = dm/ds = -2as

dv/ds = -2a

so, distance decreasing with a constant acceleration.

3. v is constant here, so v is not moving according to t, so the object is in rest.

v = c

dv/dt = 0

(assuming v is the distance)

4. here v is increasing linearly but with some initial increment. So, v = mt + c

dv/dt = m

so, v is increasing with a constant velocity.

5. v had some initial value then it's decreasing, so, v = -mt + c

dv/dt = -m

so, v is decreasing with a constant velocity.

Answered by GAUTHMATH.

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