Question

intersect at 0.
Q. RICE is a rhombus whose diagonals
If RE=13cm and RC =24cm, find EI.
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Answer 1

Answer:

⚠ _ Hello _ ⚠

Step-by-step explanation:

By PT.

(EO)^2 = (RE)^2 - (RO)^2

(EO)^2 = (13)^2-(12)^2

(EO)^2 = 169-144

(EO)^2 = 25

(EO) = 5

EI = 5*2

EI = 10cm

❇ Hope it's help❇

Answer 2

$EI=10 cm$

Step-by-step explanation:

Diagonals of rhombus are intersect at point O.

Side of rhombus=RE=13 cm

Diagonal RC=24 cm

We know that diagonals of rhombus bisect perpendicularly

Therefore, RO=OC=$\frac{1}{2}RC=\frac{1}{2}(24)=12cm$

In triangle EOR

RE=13 cm

RO=12 cm

$RE^2=EO^2+RO^2$

By using Pythagoras theorem

$(hypotenuse)^2=(Base)^2+(perpendicular\;side)^2$

Substitute the values then we get

$(13)^2=EO^2+(12)^2$

$169=EO^2+144$

$EO^2=169-144=25$

$EO=\sqrt{25}=5cm$

$EI=2\times EO=2(5)=10 cm$

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