intersection x +2y + 3 = 0 and 3x + 4y +7= 0 and as a slope =3/4
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Answer:
Slope of 3x+4y−7=0
m
1
=−
x
y
=−
3
y
Since desired line passes through x−y+z=0 and 3x+y−10=0
On solving, x=2; y=0
Equation of line which is perpendicular to 3x+4y−7=0
m
2
(x−2)=(y−4), where m
2
is slope
m
2
=
4
3
(y−4)=
4
3
(x−2)
4y−16=3x−6
3x−4y+10=0
Step-by-step explanation:
I hope it helps you
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