Question

intigration of (1-x) √x

Answer 1

If [math]u=\sqrt{1+x}[/math], then [math]x=u^2-1[/math], [math]dx=2u\, du[/math]. Now substitute: [math]\int x\sqrt{1+x} \, dx = \int \left(u^2-1\right) u \cdot 2u \, du[/math]. Take it from here now, it's simple. The answer might look slightly weird, especially near the end as you substitute back the square root, but the solution to reach it is now simple.

Answer 2

see ur answer in the image