Question

Intigration of 4x/xsqure+1

Answer 1

∫4x/(x2+1)dx Let u = x2+1 Then du = 2xdx So, 4xdx = 2du. substituting into the integral, we get 2∫(1/u)du. = 2lnlul + C. = 2ln(x2+1) + C.

mark me as brainliest

Answer 2

here is your answer. I hope this is correct