Question

Into 10 raise to the power minus 3 kg of weak acid is molar mass 60 is dissolved in a 600cc of water if 25% of acid us dissiciated what wull be depresssion in freezing point

Answer 1

Hii Hemalatha,

◆ Answer -

∆Tf = 0.0129 ℃

● Explanation -

W2 = 10^-3 kg = 1 g

M2 = 60 g/mol

W1 = 600 cc = 600 g

α = 25% = 0.25

# Solution -

Depression in freezing point is calculated by -

∆Tf = 1000.i.Kf.W2 / M2.W1

∆Tf = (1000 × 0.25 × 1.86 × 1) / (60 × 600)

∆Tf = 0.0129 ℃

Therefore, depression in freezing point will be 0.0129 ℃.

Thanks...