IntrapeziumABCD,asshown,AB//DC,AD=DC=BC=20cmand ∠A=600 Find:(i)lengthof AB (ii) distance between AB and DC
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Step-by-step explanation:
from the data the given figure is an isosceles trapezium.
Draw DM perpendicular to AB.In ∆ADM,AD is 20cm.
So,AM is 10cm.Draw CN perpendicular to AB
In∆CNB,BC is 20cm.So,BN is 10cm.
AB =10+10+20=40cm.
length of perpendicular is 10√3cm.
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