Math, asked by sidddee, 10 months ago

IntrapeziumABCD,asshown,AB//DC,AD=DC=BC=20cmand ∠A=600 Find:(i)lengthof AB (ii) distance between AB and DC

Answers

Answered by mannurusravanthi7165

0

Step-by-step explanation:

from the data the given figure is an isosceles trapezium.

Draw DM perpendicular to AB.In ∆ADM,AD is 20cm.

So,AM is 10cm.Draw CN perpendicular to AB

In∆CNB,BC is 20cm.So,BN is 10cm.

AB =10+10+20=40cm.

length of perpendicular is 10√3cm.

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