Question

intrigation of √1 + sin2x dx​

Answer 1

Answer:

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Answer 2

Answer:

∫ 1+sin2x

dx

=∫

sin

2

x+cos

2

x+2sinxcosx

dx

=∫

(sinx+cosx)

2

dx

=∫

(sinx+cosx)dx

=∫sinxdx+∫cosxdx

=−cosx+sinx+C

=sinx−cosx+C

Hence, this is the answer.