Question

intrigation of cosx / sin²x

Answer 1

Step-by-step explanation:

We have,

$\int \frac{ \cos(x) }{ \sin^{2} (x) }dx$

Put $\sin(x)=y \implies\cos(x)dx=dy$

so,

$= \int \frac{ dy }{ y^{2} }$

$= - \frac{ 1 }{ y } + C$

$= - \frac{ 1 }{ \sin(x) } + C$

$= - \cosec(x) + C$